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172 lines
7.0 KiB
172 lines
7.0 KiB
#include "merkle.h" |
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#include "hash.h" |
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#include "utilstrencodings.h" |
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/* WARNING! If you're reading this because you're learning about crypto |
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and/or designing a new system that will use merkle trees, keep in mind |
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that the following merkle tree algorithm has a serious flaw related to |
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duplicate txids, resulting in a vulnerability (CVE-2012-2459). |
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The reason is that if the number of hashes in the list at a given time |
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is odd, the last one is duplicated before computing the next level (which |
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is unusual in Merkle trees). This results in certain sequences of |
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transactions leading to the same merkle root. For example, these two |
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trees: |
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A A |
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/ \ / \ |
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B C B C |
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/ \ | / \ / \ |
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D E F D E F F |
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/ \ / \ / \ / \ / \ / \ / \ |
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1 2 3 4 5 6 1 2 3 4 5 6 5 6 |
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for transaction lists [1,2,3,4,5,6] and [1,2,3,4,5,6,5,6] (where 5 and |
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6 are repeated) result in the same root hash A (because the hash of both |
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of (F) and (F,F) is C). |
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The vulnerability results from being able to send a block with such a |
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transaction list, with the same merkle root, and the same block hash as |
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the original without duplication, resulting in failed validation. If the |
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receiving node proceeds to mark that block as permanently invalid |
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however, it will fail to accept further unmodified (and thus potentially |
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valid) versions of the same block. We defend against this by detecting |
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the case where we would hash two identical hashes at the end of the list |
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together, and treating that identically to the block having an invalid |
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merkle root. Assuming no double-SHA256 collisions, this will detect all |
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known ways of changing the transactions without affecting the merkle |
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root. |
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*/ |
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/* This implements a constant-space merkle root/path calculator, limited to 2^32 leaves. */ |
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static void MerkleComputation(const std::vector<uint256>& leaves, uint256* proot, bool* pmutated, uint32_t branchpos, std::vector<uint256>* pbranch) { |
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if (pbranch) pbranch->clear(); |
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if (leaves.size() == 0) { |
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if (pmutated) *pmutated = false; |
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if (proot) *proot = uint256(); |
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return; |
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} |
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bool mutated = false; |
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// count is the number of leaves processed so far. |
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uint32_t count = 0; |
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// inner is an array of eagerly computed subtree hashes, indexed by tree |
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// level (0 being the leaves). |
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// For example, when count is 25 (11001 in binary), inner[4] is the hash of |
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// the first 16 leaves, inner[3] of the next 8 leaves, and inner[0] equal to |
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// the last leaf. The other inner entries are undefined. |
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uint256 inner[32]; |
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// Which position in inner is a hash that depends on the matching leaf. |
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int matchlevel = -1; |
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// First process all leaves into 'inner' values. |
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while (count < leaves.size()) { |
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uint256 h = leaves[count]; |
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bool matchh = count == branchpos; |
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count++; |
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int level; |
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// For each of the lower bits in count that are 0, do 1 step. Each |
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// corresponds to an inner value that existed before processing the |
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// current leaf, and each needs a hash to combine it. |
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for (level = 0; !(count & (((uint32_t)1) << level)); level++) { |
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if (pbranch) { |
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if (matchh) { |
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pbranch->push_back(inner[level]); |
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} else if (matchlevel == level) { |
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pbranch->push_back(h); |
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matchh = true; |
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} |
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} |
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mutated |= (inner[level] == h); |
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CHash256().Write(inner[level].begin(), 32).Write(h.begin(), 32).Finalize(h.begin()); |
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} |
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// Store the resulting hash at inner position level. |
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inner[level] = h; |
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if (matchh) { |
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matchlevel = level; |
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} |
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} |
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// Do a final 'sweep' over the rightmost branch of the tree to process |
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// odd levels, and reduce everything to a single top value. |
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// Level is the level (counted from the bottom) up to which we've sweeped. |
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int level = 0; |
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// As long as bit number level in count is zero, skip it. It means there |
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// is nothing left at this level. |
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while (!(count & (((uint32_t)1) << level))) { |
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level++; |
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} |
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uint256 h = inner[level]; |
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bool matchh = matchlevel == level; |
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while (count != (((uint32_t)1) << level)) { |
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// If we reach this point, h is an inner value that is not the top. |
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// We combine it with itself (Bitcoin's special rule for odd levels in |
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// the tree) to produce a higher level one. |
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if (pbranch && matchh) { |
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pbranch->push_back(h); |
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} |
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CHash256().Write(h.begin(), 32).Write(h.begin(), 32).Finalize(h.begin()); |
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// Increment count to the value it would have if two entries at this |
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// level had existed. |
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count += (((uint32_t)1) << level); |
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level++; |
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// And propagate the result upwards accordingly. |
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while (!(count & (((uint32_t)1) << level))) { |
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if (pbranch) { |
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if (matchh) { |
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pbranch->push_back(inner[level]); |
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} else if (matchlevel == level) { |
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pbranch->push_back(h); |
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matchh = true; |
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} |
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} |
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CHash256().Write(inner[level].begin(), 32).Write(h.begin(), 32).Finalize(h.begin()); |
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level++; |
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} |
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} |
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// Return result. |
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if (pmutated) *pmutated = mutated; |
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if (proot) *proot = h; |
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} |
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uint256 ComputeMerkleRoot(const std::vector<uint256>& leaves, bool* mutated) { |
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uint256 hash; |
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MerkleComputation(leaves, &hash, mutated, -1, NULL); |
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return hash; |
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} |
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std::vector<uint256> ComputeMerkleBranch(const std::vector<uint256>& leaves, uint32_t position) { |
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std::vector<uint256> ret; |
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MerkleComputation(leaves, NULL, NULL, position, &ret); |
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return ret; |
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} |
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uint256 ComputeMerkleRootFromBranch(const uint256& leaf, const std::vector<uint256>& vMerkleBranch, uint32_t nIndex) { |
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uint256 hash = leaf; |
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for (std::vector<uint256>::const_iterator it = vMerkleBranch.begin(); it != vMerkleBranch.end(); ++it) { |
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if (nIndex & 1) { |
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hash = Hash(BEGIN(*it), END(*it), BEGIN(hash), END(hash)); |
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} else { |
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hash = Hash(BEGIN(hash), END(hash), BEGIN(*it), END(*it)); |
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} |
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nIndex >>= 1; |
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} |
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return hash; |
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} |
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uint256 BlockMerkleRoot(const CBlock& block, bool* mutated) |
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{ |
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std::vector<uint256> leaves; |
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leaves.resize(block.vtx.size()); |
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for (size_t s = 0; s < block.vtx.size(); s++) { |
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leaves[s] = block.vtx[s].GetHash(); |
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} |
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return ComputeMerkleRoot(leaves, mutated); |
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} |
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std::vector<uint256> BlockMerkleBranch(const CBlock& block, uint32_t position) |
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{ |
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std::vector<uint256> leaves; |
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leaves.resize(block.vtx.size()); |
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for (size_t s = 0; s < block.vtx.size(); s++) { |
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leaves[s] = block.vtx[s].GetHash(); |
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} |
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return ComputeMerkleBranch(leaves, position); |
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}
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