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#!/usr/bin/env python3
# Copyright (c) 2014-2016 The Bitcoin Core developers
# Distributed under the MIT software license, see the accompanying
# file COPYING or http://www.opensource.org/licenses/mit-license.php.
#
# Test pruning code
# ********
# WARNING:
# This test uses 4GB of disk space.
# This test takes 30 mins or more (up to 2 hours)
# ********
from test_framework.test_framework import BitcoinTestFramework
from test_framework.util import *
def calc_usage(blockdir):
return sum(os.path.getsize(blockdir+f) for f in os.listdir(blockdir) if os.path.isfile(blockdir+f)) / (1024. * 1024.)
class PruneTest(BitcoinTestFramework):
def __init__(self):
super().__init__()
self.setup_clean_chain = True
self.num_nodes = 3
self.utxo = []
self.address = ["",""]
self.txouts = gen_return_txouts()
def setup_network(self):
self.nodes = []
self.is_network_split = False
# Create nodes 0 and 1 to mine
self.nodes.append(start_node(0, self.options.tmpdir, ["-debug","-maxreceivebuffer=20000","-blockmaxsize=999000", "-checkblocks=5"], timewait=900))
self.nodes.append(start_node(1, self.options.tmpdir, ["-debug","-maxreceivebuffer=20000","-blockmaxsize=999000", "-checkblocks=5"], timewait=900))
# Create node 2 to test pruning
self.nodes.append(start_node(2, self.options.tmpdir, ["-debug","-maxreceivebuffer=20000","-prune=550"], timewait=900))
self.prunedir = self.options.tmpdir+"/node2/regtest/blocks/"
self.address[0] = self.nodes[0].getnewaddress()
self.address[1] = self.nodes[1].getnewaddress()
# Determine default relay fee
self.relayfee = self.nodes[0].getnetworkinfo()["relayfee"]
connect_nodes(self.nodes[0], 1)
connect_nodes(self.nodes[1], 2)
connect_nodes(self.nodes[2], 0)
sync_blocks(self.nodes[0:3])
def create_big_chain(self):
# Start by creating some coinbases we can spend later
self.nodes[1].generate(200)
sync_blocks(self.nodes[0:2])
self.nodes[0].generate(150)
# Then mine enough full blocks to create more than 550MiB of data
for i in range(645):
self.mine_full_block(self.nodes[0], self.address[0])
sync_blocks(self.nodes[0:3])
def test_height_min(self):
if not os.path.isfile(self.prunedir+"blk00000.dat"):
raise AssertionError("blk00000.dat is missing, pruning too early")
print("Success")
print("Though we're already using more than 550MiB, current usage:", calc_usage(self.prunedir))
print("Mining 25 more blocks should cause the first block file to be pruned")
# Pruning doesn't run until we're allocating another chunk, 20 full blocks past the height cutoff will ensure this
for i in range(25):
self.mine_full_block(self.nodes[0],self.address[0])
waitstart = time.time()
while os.path.isfile(self.prunedir+"blk00000.dat"):
time.sleep(0.1)
if time.time() - waitstart > 30:
raise AssertionError("blk00000.dat not pruned when it should be")
print("Success")
usage = calc_usage(self.prunedir)
print("Usage should be below target:", usage)
if (usage > 550):
raise AssertionError("Pruning target not being met")
def create_chain_with_staleblocks(self):
# Create stale blocks in manageable sized chunks
print("Mine 24 (stale) blocks on Node 1, followed by 25 (main chain) block reorg from Node 0, for 12 rounds")
for j in range(12):
# Disconnect node 0 so it can mine a longer reorg chain without knowing about node 1's soon-to-be-stale chain
# Node 2 stays connected, so it hears about the stale blocks and then reorg's when node0 reconnects
# Stopping node 0 also clears its mempool, so it doesn't have node1's transactions to accidentally mine
stop_node(self.nodes[0],0)
self.nodes[0]=start_node(0, self.options.tmpdir, ["-debug","-maxreceivebuffer=20000","-blockmaxsize=999000", "-checkblocks=5"], timewait=900)
# Mine 24 blocks in node 1
self.utxo = self.nodes[1].listunspent()
for i in range(24):
if j == 0:
self.mine_full_block(self.nodes[1],self.address[1])
else:
self.nodes[1].generate(1) #tx's already in mempool from previous disconnects
# Reorg back with 25 block chain from node 0
self.utxo = self.nodes[0].listunspent()
for i in range(25):
self.mine_full_block(self.nodes[0],self.address[0])
# Create connections in the order so both nodes can see the reorg at the same time
connect_nodes(self.nodes[1], 0)
connect_nodes(self.nodes[2], 0)
sync_blocks(self.nodes[0:3])
print("Usage can be over target because of high stale rate:", calc_usage(self.prunedir))
def reorg_test(self):
# Node 1 will mine a 300 block chain starting 287 blocks back from Node 0 and Node 2's tip
# This will cause Node 2 to do a reorg requiring 288 blocks of undo data to the reorg_test chain
# Reboot node 1 to clear its mempool (hopefully make the invalidate faster)
# Lower the block max size so we don't keep mining all our big mempool transactions (from disconnected blocks)
stop_node(self.nodes[1],1)
self.nodes[1]=start_node(1, self.options.tmpdir, ["-debug","-maxreceivebuffer=20000","-blockmaxsize=5000", "-checkblocks=5", "-disablesafemode"], timewait=900)
height = self.nodes[1].getblockcount()
print("Current block height:", height)
invalidheight = height-287
badhash = self.nodes[1].getblockhash(invalidheight)
print("Invalidating block at height:",invalidheight,badhash)
self.nodes[1].invalidateblock(badhash)
# We've now switched to our previously mined-24 block fork on node 1, but thats not what we want
# So invalidate that fork as well, until we're on the same chain as node 0/2 (but at an ancestor 288 blocks ago)
mainchainhash = self.nodes[0].getblockhash(invalidheight - 1)
curhash = self.nodes[1].getblockhash(invalidheight - 1)
while curhash != mainchainhash:
self.nodes[1].invalidateblock(curhash)
curhash = self.nodes[1].getblockhash(invalidheight - 1)
assert(self.nodes[1].getblockcount() == invalidheight - 1)
print("New best height", self.nodes[1].getblockcount())
# Reboot node1 to clear those giant tx's from mempool
stop_node(self.nodes[1],1)
self.nodes[1]=start_node(1, self.options.tmpdir, ["-debug","-maxreceivebuffer=20000","-blockmaxsize=5000", "-checkblocks=5", "-disablesafemode"], timewait=900)
print("Generating new longer chain of 300 more blocks")
self.nodes[1].generate(300)
print("Reconnect nodes")
connect_nodes(self.nodes[0], 1)
connect_nodes(self.nodes[2], 1)
sync_blocks(self.nodes[0:3])
print("Verify height on node 2:",self.nodes[2].getblockcount())
print("Usage possibly still high bc of stale blocks in block files:", calc_usage(self.prunedir))
print("Mine 220 more blocks so we have requisite history (some blocks will be big and cause pruning of previous chain)")
self.nodes[0].generate(220) #node 0 has many large tx's in its mempool from the disconnects
sync_blocks(self.nodes[0:3])
usage = calc_usage(self.prunedir)
print("Usage should be below target:", usage)
if (usage > 550):
raise AssertionError("Pruning target not being met")
return invalidheight,badhash
def reorg_back(self):
# Verify that a block on the old main chain fork has been pruned away
try:
self.nodes[2].getblock(self.forkhash)
raise AssertionError("Old block wasn't pruned so can't test redownload")
except JSONRPCException as e:
print("Will need to redownload block",self.forkheight)
# Verify that we have enough history to reorg back to the fork point
# Although this is more than 288 blocks, because this chain was written more recently
# and only its other 299 small and 220 large block are in the block files after it,
# its expected to still be retained
self.nodes[2].getblock(self.nodes[2].getblockhash(self.forkheight))
first_reorg_height = self.nodes[2].getblockcount()
curchainhash = self.nodes[2].getblockhash(self.mainchainheight)
self.nodes[2].invalidateblock(curchainhash)
goalbestheight = self.mainchainheight
goalbesthash = self.mainchainhash2
# As of 0.10 the current block download logic is not able to reorg to the original chain created in
# create_chain_with_stale_blocks because it doesn't know of any peer thats on that chain from which to
# redownload its missing blocks.
# Invalidate the reorg_test chain in node 0 as well, it can successfully switch to the original chain
# because it has all the block data.
# However it must mine enough blocks to have a more work chain than the reorg_test chain in order
# to trigger node 2's block download logic.
# At this point node 2 is within 288 blocks of the fork point so it will preserve its ability to reorg
if self.nodes[2].getblockcount() < self.mainchainheight:
blocks_to_mine = first_reorg_height + 1 - self.mainchainheight
print("Rewind node 0 to prev main chain to mine longer chain to trigger redownload. Blocks needed:", blocks_to_mine)
self.nodes[0].invalidateblock(curchainhash)
assert(self.nodes[0].getblockcount() == self.mainchainheight)
assert(self.nodes[0].getbestblockhash() == self.mainchainhash2)
goalbesthash = self.nodes[0].generate(blocks_to_mine)[-1]
goalbestheight = first_reorg_height + 1
print("Verify node 2 reorged back to the main chain, some blocks of which it had to redownload")
waitstart = time.time()
while self.nodes[2].getblockcount() < goalbestheight:
time.sleep(0.1)
if time.time() - waitstart > 900:
raise AssertionError("Node 2 didn't reorg to proper height")
assert(self.nodes[2].getbestblockhash() == goalbesthash)
# Verify we can now have the data for a block previously pruned
assert(self.nodes[2].getblock(self.forkhash)["height"] == self.forkheight)
def mine_full_block(self, node, address):
# Want to create a full block
# We'll generate a 66k transaction below, and 14 of them is close to the 1MB block limit
for j in range(14):
if len(self.utxo) < 14:
self.utxo = node.listunspent()
inputs=[]
outputs = {}
t = self.utxo.pop()
inputs.append({ "txid" : t["txid"], "vout" : t["vout"]})
remchange = t["amount"] - 100*self.relayfee # Fee must be above min relay rate for 66kb tx
outputs[address]=remchange
# Create a basic transaction that will send change back to ourself after account for a fee
# And then insert the 128 generated transaction outs in the middle rawtx[92] is where the #
# of txouts is stored and is the only thing we overwrite from the original transaction
rawtx = node.createrawtransaction(inputs, outputs)
newtx = rawtx[0:92]
newtx = newtx + self.txouts
newtx = newtx + rawtx[94:]
# Appears to be ever so slightly faster to sign with SIGHASH_NONE
signresult = node.signrawtransaction(newtx,None,None,"NONE")
txid = node.sendrawtransaction(signresult["hex"], True)
# Mine a full sized block which will be these transactions we just created
node.generate(1)
def run_test(self):
print("Warning! This test requires 4GB of disk space and takes over 30 mins (up to 2 hours)")
print("Mining a big blockchain of 995 blocks")
self.create_big_chain()
# Chain diagram key:
# * blocks on main chain
# +,&,$,@ blocks on other forks
# X invalidated block
# N1 Node 1
#
# Start by mining a simple chain that all nodes have
# N0=N1=N2 **...*(995)
print("Check that we haven't started pruning yet because we're below PruneAfterHeight")
self.test_height_min()
# Extend this chain past the PruneAfterHeight
# N0=N1=N2 **...*(1020)
print("Check that we'll exceed disk space target if we have a very high stale block rate")
self.create_chain_with_staleblocks()
# Disconnect N0
# And mine a 24 block chain on N1 and a separate 25 block chain on N0
# N1=N2 **...*+...+(1044)
# N0 **...**...**(1045)
#
# reconnect nodes causing reorg on N1 and N2
# N1=N2 **...*(1020) *...**(1045)
# \
# +...+(1044)
#
# repeat this process until you have 12 stale forks hanging off the
# main chain on N1 and N2
# N0 *************************...***************************(1320)
#
# N1=N2 **...*(1020) *...**(1045) *.. ..**(1295) *...**(1320)
# \ \ \
# +...+(1044) &.. $...$(1319)
# Save some current chain state for later use
self.mainchainheight = self.nodes[2].getblockcount() #1320
self.mainchainhash2 = self.nodes[2].getblockhash(self.mainchainheight)
print("Check that we can survive a 288 block reorg still")
(self.forkheight,self.forkhash) = self.reorg_test() #(1033, )
# Now create a 288 block reorg by mining a longer chain on N1
# First disconnect N1
# Then invalidate 1033 on main chain and 1032 on fork so height is 1032 on main chain
# N1 **...*(1020) **...**(1032)X..
# \
# ++...+(1031)X..
#
# Now mine 300 more blocks on N1
# N1 **...*(1020) **...**(1032) @@...@(1332)
# \ \
# \ X...
# \ \
# ++...+(1031)X.. ..
#
# Reconnect nodes and mine 220 more blocks on N1
# N1 **...*(1020) **...**(1032) @@...@@@(1552)
# \ \
# \ X...
# \ \
# ++...+(1031)X.. ..
#
# N2 **...*(1020) **...**(1032) @@...@@@(1552)
# \ \
# \ *...**(1320)
# \ \
# ++...++(1044) ..
#
# N0 ********************(1032) @@...@@@(1552)
# \
# *...**(1320)
print("Test that we can rerequest a block we previously pruned if needed for a reorg")
self.reorg_back()
# Verify that N2 still has block 1033 on current chain (@), but not on main chain (*)
# Invalidate 1033 on current chain (@) on N2 and we should be able to reorg to
# original main chain (*), but will require redownload of some blocks
# In order to have a peer we think we can download from, must also perform this invalidation
# on N0 and mine a new longest chain to trigger.
# Final result:
# N0 ********************(1032) **...****(1553)
# \
# X@...@@@(1552)
#
# N2 **...*(1020) **...**(1032) **...****(1553)
# \ \
# \ X@...@@@(1552)
# \
# +..
#
# N1 doesn't change because 1033 on main chain (*) is invalid
print("Done")
if __name__ == '__main__':
PruneTest().main()