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166 lines
8.0 KiB
166 lines
8.0 KiB
#!/usr/bin/env python3 |
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# Copyright (c) 2014-2017 The Bitcoin Core developers |
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# Distributed under the MIT software license, see the accompanying |
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# file COPYING or http://www.opensource.org/licenses/mit-license.php. |
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"""Test the abandontransaction RPC. |
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The abandontransaction RPC marks a transaction and all its in-wallet |
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descendants as abandoned which allows their inputs to be respent. It can be |
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used to replace "stuck" or evicted transactions. It only works on transactions |
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which are not included in a block and are not currently in the mempool. It has |
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no effect on transactions which are already conflicted or abandoned. |
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""" |
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from test_framework.test_framework import BitcoinTestFramework |
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from test_framework.util import * |
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class AbandonConflictTest(BitcoinTestFramework): |
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def set_test_params(self): |
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self.num_nodes = 2 |
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self.extra_args = [["-minrelaytxfee=0.00001"], []] |
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def run_test(self): |
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self.nodes[1].generate(100) |
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sync_blocks(self.nodes) |
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balance = self.nodes[0].getbalance() |
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txA = self.nodes[0].sendtoaddress(self.nodes[0].getnewaddress(), Decimal("10")) |
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txB = self.nodes[0].sendtoaddress(self.nodes[0].getnewaddress(), Decimal("10")) |
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txC = self.nodes[0].sendtoaddress(self.nodes[0].getnewaddress(), Decimal("10")) |
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sync_mempools(self.nodes) |
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self.nodes[1].generate(1) |
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sync_blocks(self.nodes) |
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newbalance = self.nodes[0].getbalance() |
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assert(balance - newbalance < Decimal("0.1")) #no more than fees lost |
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balance = newbalance |
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# Disconnect nodes so node0's transactions don't get into node1's mempool |
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disconnect_nodes(self.nodes[0], 1) |
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# Identify the 10btc outputs |
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nA = next(i for i, vout in enumerate(self.nodes[0].getrawtransaction(txA, 1)["vout"]) if vout["value"] == Decimal("10")) |
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nB = next(i for i, vout in enumerate(self.nodes[0].getrawtransaction(txB, 1)["vout"]) if vout["value"] == Decimal("10")) |
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nC = next(i for i, vout in enumerate(self.nodes[0].getrawtransaction(txC, 1)["vout"]) if vout["value"] == Decimal("10")) |
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inputs =[] |
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# spend 10btc outputs from txA and txB |
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inputs.append({"txid":txA, "vout":nA}) |
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inputs.append({"txid":txB, "vout":nB}) |
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outputs = {} |
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outputs[self.nodes[0].getnewaddress()] = Decimal("14.99998") |
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outputs[self.nodes[1].getnewaddress()] = Decimal("5") |
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signed = self.nodes[0].signrawtransaction(self.nodes[0].createrawtransaction(inputs, outputs)) |
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txAB1 = self.nodes[0].sendrawtransaction(signed["hex"]) |
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# Identify the 14.99998btc output |
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nAB = next(i for i, vout in enumerate(self.nodes[0].getrawtransaction(txAB1, 1)["vout"]) if vout["value"] == Decimal("14.99998")) |
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#Create a child tx spending AB1 and C |
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inputs = [] |
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inputs.append({"txid":txAB1, "vout":nAB}) |
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inputs.append({"txid":txC, "vout":nC}) |
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outputs = {} |
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outputs[self.nodes[0].getnewaddress()] = Decimal("24.9996") |
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signed2 = self.nodes[0].signrawtransaction(self.nodes[0].createrawtransaction(inputs, outputs)) |
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txABC2 = self.nodes[0].sendrawtransaction(signed2["hex"]) |
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# Create a child tx spending ABC2 |
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signed3_change = Decimal("24.999") |
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inputs = [ {"txid":txABC2, "vout":0} ] |
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outputs = { self.nodes[0].getnewaddress(): signed3_change } |
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signed3 = self.nodes[0].signrawtransaction(self.nodes[0].createrawtransaction(inputs, outputs)) |
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# note tx is never directly referenced, only abandoned as a child of the above |
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self.nodes[0].sendrawtransaction(signed3["hex"]) |
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# In mempool txs from self should increase balance from change |
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newbalance = self.nodes[0].getbalance() |
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assert_equal(newbalance, balance - Decimal("30") + signed3_change) |
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balance = newbalance |
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# Restart the node with a higher min relay fee so the parent tx is no longer in mempool |
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# TODO: redo with eviction |
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self.stop_node(0) |
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self.start_node(0, extra_args=["-minrelaytxfee=0.0001"]) |
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# Verify txs no longer in either node's mempool |
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assert_equal(len(self.nodes[0].getrawmempool()), 0) |
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assert_equal(len(self.nodes[1].getrawmempool()), 0) |
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# Not in mempool txs from self should only reduce balance |
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# inputs are still spent, but change not received |
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newbalance = self.nodes[0].getbalance() |
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assert_equal(newbalance, balance - signed3_change) |
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# Unconfirmed received funds that are not in mempool, also shouldn't show |
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# up in unconfirmed balance |
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unconfbalance = self.nodes[0].getunconfirmedbalance() + self.nodes[0].getbalance() |
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assert_equal(unconfbalance, newbalance) |
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# Also shouldn't show up in listunspent |
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assert(not txABC2 in [utxo["txid"] for utxo in self.nodes[0].listunspent(0)]) |
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balance = newbalance |
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# Abandon original transaction and verify inputs are available again |
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# including that the child tx was also abandoned |
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self.nodes[0].abandontransaction(txAB1) |
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newbalance = self.nodes[0].getbalance() |
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assert_equal(newbalance, balance + Decimal("30")) |
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balance = newbalance |
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# Verify that even with a low min relay fee, the tx is not reaccepted from wallet on startup once abandoned |
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self.stop_node(0) |
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self.start_node(0, extra_args=["-minrelaytxfee=0.00001"]) |
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assert_equal(len(self.nodes[0].getrawmempool()), 0) |
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assert_equal(self.nodes[0].getbalance(), balance) |
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# But if its received again then it is unabandoned |
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# And since now in mempool, the change is available |
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# But its child tx remains abandoned |
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self.nodes[0].sendrawtransaction(signed["hex"]) |
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newbalance = self.nodes[0].getbalance() |
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assert_equal(newbalance, balance - Decimal("20") + Decimal("14.99998")) |
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balance = newbalance |
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# Send child tx again so its unabandoned |
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self.nodes[0].sendrawtransaction(signed2["hex"]) |
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newbalance = self.nodes[0].getbalance() |
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assert_equal(newbalance, balance - Decimal("10") - Decimal("14.99998") + Decimal("24.9996")) |
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balance = newbalance |
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# Remove using high relay fee again |
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self.stop_node(0) |
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self.start_node(0, extra_args=["-minrelaytxfee=0.0001"]) |
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assert_equal(len(self.nodes[0].getrawmempool()), 0) |
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newbalance = self.nodes[0].getbalance() |
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assert_equal(newbalance, balance - Decimal("24.9996")) |
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balance = newbalance |
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# Create a double spend of AB1 by spending again from only A's 10 output |
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# Mine double spend from node 1 |
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inputs =[] |
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inputs.append({"txid":txA, "vout":nA}) |
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outputs = {} |
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outputs[self.nodes[1].getnewaddress()] = Decimal("9.9999") |
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tx = self.nodes[0].createrawtransaction(inputs, outputs) |
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signed = self.nodes[0].signrawtransaction(tx) |
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self.nodes[1].sendrawtransaction(signed["hex"]) |
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self.nodes[1].generate(1) |
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connect_nodes(self.nodes[0], 1) |
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sync_blocks(self.nodes) |
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# Verify that B and C's 10 BTC outputs are available for spending again because AB1 is now conflicted |
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newbalance = self.nodes[0].getbalance() |
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assert_equal(newbalance, balance + Decimal("20")) |
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balance = newbalance |
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# There is currently a minor bug around this and so this test doesn't work. See Issue #7315 |
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# Invalidate the block with the double spend and B's 10 BTC output should no longer be available |
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# Don't think C's should either |
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self.nodes[0].invalidateblock(self.nodes[0].getbestblockhash()) |
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newbalance = self.nodes[0].getbalance() |
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#assert_equal(newbalance, balance - Decimal("10")) |
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self.log.info("If balance has not declined after invalidateblock then out of mempool wallet tx which is no longer") |
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self.log.info("conflicted has not resumed causing its inputs to be seen as spent. See Issue #7315") |
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self.log.info(str(balance) + " -> " + str(newbalance) + " ?") |
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if __name__ == '__main__': |
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AbandonConflictTest().main() |