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Fix natural sorting when the common part of 2 strings ends partially in a number which continues in the uncommon part.

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Closes #8080 #6732.
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sledgehammer999 2017-12-21 15:01:13 +02:00
parent b8277614ec
commit 5437974b85
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1 changed files with 4 additions and 1 deletions
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5
src/base/utils/string.cpp
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@ -85,7 +85,10 @@ namespace
const QChar leftChar = (m_caseSensitivity == Qt::CaseSensitive) ? left[posL] : left[posL].toLower(); const QChar leftChar = (m_caseSensitivity == Qt::CaseSensitive) ? left[posL] : left[posL].toLower();
const QChar rightChar = (m_caseSensitivity == Qt::CaseSensitive) ? right[posR] : right[posR].toLower(); const QChar rightChar = (m_caseSensitivity == Qt::CaseSensitive) ? right[posR] : right[posR].toLower();
if (leftChar == rightChar) { // Compare only non-digits.
// Numbers should be compared as a whole
// otherwise the string->int conversion can yield a wrong value
if ((leftChar == rightChar) && !leftChar.isDigit()) {
// compare next character // compare next character
++posL; ++posL;
++posR; ++posR;