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Repeating on timeout in ztex could make the code never return.

nfactor-troky
Con Kolivas 13 years ago
parent
commit
a916be0b09
  1. 6
      libztex.c

6
libztex.c

@ -618,8 +618,7 @@ int libztex_sendHashData(struct libztex_device *ztex, unsigned char *sendbuf) @@ -618,8 +618,7 @@ int libztex_sendHashData(struct libztex_device *ztex, unsigned char *sendbuf)
ret -= cnt;
len += cnt;
} else
if (cnt != LIBUSB_ERROR_TIMEOUT)
break;
break;
}
if (unlikely(cnt < 0))
applog(LOG_ERR, "%s: Failed sendHashData with err %d", ztex->repr, cnt);
@ -647,8 +646,7 @@ int libztex_readHashData(struct libztex_device *ztex, struct libztex_hash_data n @@ -647,8 +646,7 @@ int libztex_readHashData(struct libztex_device *ztex, struct libztex_hash_data n
ret -= cnt;
len += cnt;
} else
if (cnt != LIBUSB_ERROR_TIMEOUT)
break;
break;
}
if (unlikely(cnt < 0)) {

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