Uranium-235: 200 MeV per fission Uranium-233: 197 MeV per fission Plutonium-239: 210 MeV per fission The amount of energy needed to reach 15,111 megatons is: E = 15.111 × 10^6 × 4.184 × 10^12 Joules, where 4.184 × 10^12 Joules is the conversion of 1 megaton to Joules. Now we can calculate the number of fissions needed to each element, considering the efficiency of 0.147: For Uranium-235: N_fissions_Uranium-235 = E / (Efficiency × Energy per fission) N_fissions_Uranium-235 = 15.111 × 10^6 × 4.184 × 10^12 / (0.147 × 200) N_fissions_Uranium-235 ≈ 5,351 × 10^17 fissions For Uranium-233: N_fissions_Uranium-233 = E / (Efficiency × Energy per fission) N_fissions_Uranium-233 = 15.111 × 10^6 × 4.184 × 10^12 / (0.147 × 197) N_fissions_Uranium-233 ≈ 5,442 × 10^17 fissions For Plutonium-239: N_fissions_Plutonium-239 = E / (Efficiency × Energy per fission) N_fissions_Plutonium-239 = 15.111 × 10^6 × 4.184 × 10^12 / (0.147 × 210) N_fissions_Plutonium-239 ≈ 5057 × 10^17 fissions Finally, we can calculate the amount of mass of each element needed, considering the number of fissions and the molar mass of each element: For Uranium-235: m_Uranium-235 = N_fissions_Uranium-235 × Molar mass of Uranium-235 / Avogadro's number The molar mass of Uranium-235 is approximately 235 g/mol. For Uranium-233: m_Uranium-233 = N_fissions_Uranium-233 × Molar mass of Uranium-233 / Avogadro's number The molar mass of Uranium-233 is approximately 233 g/mol. For Plutonium-239: m_Plutonium-239 = N_fissions_Plutonium-239 × Molar Mass of Plutonium-239 / Avogadro's Number The molar mass of Plutonium-239 is approximately 239 g/mol. Now we can calculate the masses: For Uranium-235: m_Uranium-235 = 5.351 × 10^17 × 235 / 6.022 × 10^23 m_Uranium-235 ≈ 21.04 kg For Uranium-233: m_Uranium-233 = 5.442 × 10^17 × 233 / 6.022 × 10^23 m_Uranium-233 ≈ 21.43 kg For Plutonium-239: m_Plutonium-239 = 5.057 × 10^17 × 239 / 6.022 × 10^23 m_Plutonium-239 ≈ 19.97 Now we can calculate the required masses of each element to reach 15,111 megatons of energy: For Uranium-235: m_Uranium-235 = 5.351 × 10^17 × 235 / 6.022 × 10^23 m_Uranium-235 ≈ 21.04 kg For Uranium-233: m_Uranium-233 = 5.442 × 10^17 × 233 / 6.022 × 10^23 m_Uranium-233 ≈ 21.43 kg For Plutonium-239: m_Plutonium-239 = 5.057 × 10^17 × 239 / 6.022 × 10^23 m_Plutonium-239 ≈ 19.97 kg Therefore, to reach 15,111 megatons of energy, It would take approximately: 21.04 kg of Uranium-235 21.43 kg of Uranium-233 19.97 kg of Plutonium-239